选读SQL经典实例笔记13_case与聚合

2023-07-27 18:09:20
来源:博客园


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1.识别非小计行

1.1.结果集

1.2.DB2

1.3.Oracle

1.4.超级聚合(supera ggregate)值

1.4.1.sql

select deptno, job, sum(sal) sal,       grouping(deptno) deptno_subtotals,       grouping(job) job_subtotals  from emp group by cube(deptno,job)

1.5.SQL Server

1.5.1.sql

select deptno, job, sum(sal) sal,        grouping(deptno) deptno_subtotals,        grouping(job) job_subtotals   from emp  group by deptno,job with cube

2.使用CASE表达式标记行数据

2.1.结果集

2.2.sql

select ename,       case when job = "CLERK"            then 1 else 0       end as is_clerk,       case when job = "SALESMAN"            then 1 else 0       end as is_sales,       case when job = "MANAGER"            then 1 else 0       end as is_mgr,       case when job = "ANALYST"            then 1 else 0       end as is_analyst,       case when job = "PRESIDENT"            then 1 else 0       end as is_prez  from emp order by 2,3,4,5,6

3.创建稀疏矩阵

3.1.结果集

3.2.sql

select case deptno when 10 then ename end as d10,       case deptno when 20 then ename end as d20,       case deptno when 30 then ename end as d30,       case job when "CLERK"     then ename end as clerks,       case job when "MANAGER"   then ename end as mgrs,       case job when "PRESIDENT" then ename end as prez,       case job when "ANALYST"   then ename end as anals,       case job when "SALESMAN"  then ename end as sales  from emp

3.3.sql

select max(case deptno when 10 then ename end) d10,       max(case deptno when 20 then ename end) d20,       max(case deptno when 30 then ename end) d30,       max(case job when "CLERK"     then ename end) clerks,       max(case job when "MANAGER"   then ename end) mgrs,       max(case job when "PRESIDENT" then ename end) prez,       max(case job when "ANALYST"   then ename end) anals,       max(case job when "SALESMAN" then ename end) sales  from (select deptno, job, ename,       row_number()over(partition by deptno order by empno) rn  from emp       ) x group by rn

3.3.1.删除一些Null行,以便让整个报表显得“紧密”一些

4.按照时间单位分组

4.1.结果集

4.1.1.sql

select trx_id,       trx_date,       trx_cnt  from trx_logTRX_ID TRX_DATE                TRX_CNT------ -------------------- ----------     1 28-JUL-2005 19:03:07         44     2 28-JUL-2005 19:03:08         18     3 28-JUL-2005 19:03:09         23     4 28-JUL-2005 19:03:10         29     5 28-JUL-2005 19:03:11         27     6 28-JUL-2005 19:03:12         45     7 28-JUL-2005 19:03:13         45     8 28-JUL-2005 19:03:14         32     9 28-JUL-2005 19:03:15         41    10 28-JUL-2005 19:03:16         15    11 28-JUL-2005 19:03:17         24    12 28-JUL-2005 19:03:18         47    13 28-JUL-2005 19:03:19         37    14 28-JUL-2005 19:03:20         48    15 28-JUL-2005 19:03:21         46    16 28-JUL-2005 19:03:22         44    17 28-JUL-2005 19:03:23         36    18 28-JUL-2005 19:03:24         41    19 28-JUL-2005 19:03:25         33    20 28-JUL-2005 19:03:26         19

4.1.2.结果集

GRP TRX_START            TRX_END                   TOTAL--- -------------------- -------------------- ----------  1 28-JUL-2005 19:03:07 28-JUL-2005 19:03:11        141  2 28-JUL-2005 19:03:12 28-JUL-2005 19:03:16        178  3 28-JUL-2005 19:03:17 28-JUL-2005 19:03:21        202  4 28-JUL-2005 19:03:22 28-JUL-2005 19:03:26        173

4.2.sql

select ceil(trx_id/5.0) as grp,       min(trx_date)    as trx_start,       max(trx_date)    as trx_end,       sum(trx_cnt)     as total  from trx_log group by ceil(trx_id/5.0)

5.多维度聚合运算

5.1.结果集

5.2.DB2

5.3.Oracle

5.4.SQL Server

5.5.窗口函数COUNT OVER

5.5.1.sql

select ename,       deptno,       count(*)over(partition by deptno) deptno_cnt,       job,       count(*)over(partition by job) job_cnt,       count(*)over() total  from emp

5.6.PostgreSQL

5.7.MySQL

5.8.使用标量子查询

5.8.1.sql

select e.ename,       e.deptno,       (select count(*) from emp d         where d.deptno = e.deptno) as deptno_cnt,       job,       (select count(*) from emp d         where d.job = e.job) as job_cnt,       (select count(*) from emp) as total  from emp e

6.动态区间聚合运算

6.1.入职最早的员工的HIREDATE作为起始点,每隔90天计算一次工资合计值

6.1.1.结果集

HIREDATE        SAL SPENDING_PATTERN----------- ------- ----------------17-DEC-1980     800              80020-FEB-1981    1600             240022-FEB-1981    1250             365002-APR-1981    2975             582501-MAY-1981    2850             867509-JUN-1981    2450             827508-SEP-1981    1500             150028-SEP-1981    1250             275017-NOV-1981    5000             775003-DEC-1981     950            1170003-DEC-1981    3000            1170023-JAN-1982    1300            1025009-DEC-1982    3000             300012-JAN-1983    1100             4100

6.2.DB2

6.3.Oracle

6.4.窗口函数SUM OVER

6.4.1.sql

select hiredat,       sal,       sum(sal)over(order by days(hiredate)                       range between 90 preceding                         and current row) spending_pattern  from emp e

6.4.2.sql

select hiredate,       sal,       sum(sal)over(order by hiredate                       range between 90 preceding                         and current row) spending_pattern  from emp e

6.4.2.1.Oracle的窗口函数支持DATE类型排序

6.5.PostgreSQL

6.6.MySQL

6.7.SQL Server

6.8.使用标量子查询

6.8.1.sql

select e.hiredate,       e.sal,       (select sum(sal) from emp d         where d.hiredate between e.hiredate-90                              and e.hiredate) as spending_pattern  from emp e order by 1

7.变换带有小计的结果集

7.1.结果集

7.2.DB2

7.3.Oracle

7.4.使用GROUP BY的ROLLUP扩展

7.4.1.sql

select mgr,        sum(case deptno when 10 then sal else 0 end) dept10,        sum(case deptno when 20 then sal else 0 end) dept20,        sum(case deptno when 30 then sal else 0 end) dept30,        sum(case flag when "11" then sal else null end) total   from ( select deptno,mgr,sum(sal) sal,        cast(grouping(deptno) as char(1))||        cast(grouping(mgr) as char(1)) flag   from emp  where mgr is not null  group by rollup(deptno,mgr)        ) x  group by mgr

7.5.SQL Server

7.5.1.sql

select mgr,       sum(case deptno when 10 then sal else 0 end) dept10,       sum(case deptno when 20 then sal else 0 end) dept20,       sum(case deptno when 30 then sal else 0 end) dept30,       sum(case flag   when "11" then sal else null end) total  from (select deptno,mgr,sum(sal) sal,       cast(grouping(deptno) as char(1))+       cast(grouping(mgr)    as char(1)) flag  from emp where mgr is not null group by deptno,mgr with rollup       ) x group by mgr

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